indefinite-integration

Question: $\int_{{}}^{{}}{\frac{10{{x}^{9}}+{{10}^{x}}{{\log }_{e}}10}{{{10}^{x}}+{{x}^{10}}}}\ dx=$

1) $-\frac{1}{2}\frac{1}{{{({{10}^{x}}+{{x}^{10}})}^{2}}}+c$

2) $\log ({{10}^{x}}+{{x}^{10}})+c$

3) $\frac{1}{2}\frac{1}{{{({{10}^{x}}+{{x}^{10}})}^{2}}}+c$

4) None of these

Solution:

Explanation: No Explanation

Integration by substitution

Rate this question:

★ ★ ★ ★ ★

Average rating: (0 votes)