indefinite-integration

Related Questions

• $\int_{{}}^{{}}{\frac{1+\tan x}{x+\log \sec x}\ dx=}$

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• $\int{\frac{1+{{\tan }^{2}}x}{1-{{\tan }^{2}}x}\,dx}$ equals to

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• $\int_{{}}^{{}}{\frac{dx}{{{e}^{x}}-1}=}$

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• $\int{\sqrt{\frac{1+x}{1-x}}\,\,dx=}$

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• $\int_{{}}^{{}}{\frac{{{e}^{2x}}+1}{{{e}^{2x}}-1}\ dx}$ equals

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