indefinite-integration

Question: $\int_{{}}^{{}}{\frac{1}{\sqrt{1-{{e}^{2x}}}}\ dx=}$



1) $x-\log [1+\sqrt{1-{{e}^{2x}}}]+c$
2) $x+\log [1+\sqrt{1-{{e}^{2x}}}]+c$
3) $\log [1+\sqrt{1-{{e}^{2x}}}]-x+c$
4) None of these
Solution: Explanation: No Explanation
Integration by substitution

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