indefinite-integration

Question: $\int_{{}}^{{}}{\frac{{{e}^{-x}}}{1+{{e}^{x}}}\ dx=}$



1) $\log (1+{{e}^{x}})-x-{{e}^{-x}}+c$
2) $\log (1+{{e}^{x}})+x-{{e}^{-x}}+c$
3) $\log (1+{{e}^{x}})-x+{{e}^{-x}}+c$
4) $\log (1+{{e}^{x}})+x+{{e}^{-x}}+c$
Solution: Explanation: No Explanation
Integration by substitution

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