indefinite-integration

Question: $\int_{{}}^{{}}{\frac{1}{\sqrt{x}}{{\tan }^{4}}\sqrt{x}}{{\sec }^{2}}\sqrt{x}\ dx=$

1) $2{{\tan }^{5}}\sqrt{x}+c$

2) $\frac{1}{5}{{\tan }^{5}}\sqrt{x}+c$

3) $\frac{2}{5}{{\tan }^{5}}\sqrt{x}+c$

4) None of these

Solution:

Explanation: No Explanation

Integration by substitution

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