indefinite-integration

Question: $\int_{{}}^{{}}{\frac{dx}{{{e}^{x}}+{{e}^{-x}}}=}$

1) ${{\tan }^{-1}}({{e}^{-x}})$

2) ${{\tan }^{-1}}({{e}^{x}})$

3) $\log ({{e}^{x}}-{{e}^{-x}})$

4) $\log ({{e}^{x}}+{{e}^{-x}})$

Solution:

Explanation: No Explanation

Integration by substitution

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