indefinite-integration

Question: $\int_{{}}^{{}}{\frac{dx}{{{e}^{-2x}}{{({{e}^{2x}}+1)}^{2}}}=}$

1) $\frac{-1}{2({{e}^{2x}}+1)}+c$

2) $\frac{1}{2({{e}^{2x}}+1)}+c$

3) $\frac{1}{{{e}^{2x}}+1}+c$

4) $\frac{-1}{{{e}^{2x}}+1}+c$

Solution:

Explanation: No Explanation

Integration by substitution

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