indefinite-integration

Question: $\int_{{}}^{{}}{x\sqrt{1+{{x}^{2}}}}\ dx=$



1) $\frac{1+2{{x}^{2}}}{\sqrt{1+{{x}^{2}}}}+c$
2) $\sqrt{1+{{x}^{2}}}+c$
3) $3{{(1+{{x}^{2}})}^{3/2}}+c$
4) $\frac{1}{3}{{(1+{{x}^{2}})}^{3/2}}+c$
Solution: Explanation: No Explanation
Integration by substitution

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