inv-trig

Question: If ${{x}^{2}}+{{y}^{2}}+{{z}^{2}}={{r}^{2}}$, then ${{\tan }^{-1}}\left( \frac{xy}{zr} \right)+$ ${{\tan }^{-1}}\left( \frac{yz}{xr} \right)+\tan \left( \frac{zx}{yr} \right)=$



1) $\pi $
2) $\frac{\pi }{2}$
3) 0
4) None of these
Solution: Explanation: No Explanation
Inverse trigonometric functions

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