inv-trig

Question: If ${{\cos }^{-1}}x+{{\cos }^{-1}}y+{{\cos }^{-1}}z=\pi $, then

1) ${{x}^{2}}+{{y}^{2}}+{{z}^{2}}+xyz=0$

2) ${{x}^{2}}+{{y}^{2}}+{{z}^{2}}+2xyz=0$

3) ${{x}^{2}}+{{y}^{2}}+{{z}^{2}}+xyz=1$

4) ${{x}^{2}}+{{y}^{2}}+{{z}^{2}}+2xyz=1$

Solution:

Explanation: No Explanation

Inverse trigonometric functions

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