inv-trig

Question: ${{\cot }^{-1}}\frac{3}{4}+{{\sin }^{-1}}\frac{5}{13}=$



1) ${{\sin }^{-1}}\frac{63}{65}$
2) ${{\sin }^{-1}}\frac{12}{13}$
3) ${{\sin }^{-1}}\frac{65}{68}$
4) ${{\sin }^{-1}}\frac{5}{12}$
Solution: Explanation: No Explanation
Inverse trigonometric functions

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