inv-trig

Question: A solution of the equation ${{\tan }^{-1}}(1+x)$ $+{{\tan }^{-1}}(1-x)$ $=\frac{\pi }{2}$ is



1) $x=1$
2) $x=-1$
3) $x=0$
4) $x=\pi $
Solution: Explanation: No Explanation
Inverse trigonometric functions

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