Questions in inv-trig

Select	Question
	If ${{\cos }^{-1}}\left( \frac{1}{x} \right)= \theta $, then $\tan \theta =$
	$\sin ({{\cot }^{-1}}x)$
	$\cos \text{ }\left( {{\sin }^{-1}}\frac{5}{13} \right)=$
	${{\cot }^{-1}}(-\sqrt{3})$=
	$1+{{\cot }^{2}}({{\sin }^{-1}}x)=$
	If ${{\sin }^{-1}}\frac{1}{2}={{\tan }^{-1}}x,$then $x =$
	${{\tan }^{-1}}\left( \frac{\sqrt{1+{{x}^{2}}}-1}{x} \right)=$
	${{\tan }^{-1}}\frac{x}{\sqrt{{{a}^{2}}-{{x}^{2}}}}=$
	$\cos ({{\tan }^{-1}}x)=$
	$\tan \left[ {{\sec }^{-1}}\sqrt{1+{{x}^{2}}} \right]=$

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