inv-trig

Question: If ${{\cos }^{-1}}\left( \frac{1}{x} \right)= \theta $, then $\tan \theta =$



1) $\frac{1}{\sqrt{{{x}^{2}}-1}}$
2) $\sqrt{{{x}^{2}}+1}$
3) $\sqrt{1-{{x}^{2}}}$
4) $\sqrt{{{x}^{2}}-1}$
Solution: Explanation: No Explanation
Inverse trigonometric functions

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