inv-trig

Question: If ${{\tan }^{-1}}(x-1)+{{\tan }^{-1}}x+{{\tan }^{-1}}(x+1)={{\tan }^{-1}}3x$,then x =



1) $\pm \frac{1}{2}$
2) $0,\,\frac{1}{2}$
3) $0,\,-\frac{1}{2}$
4) $0,\,\pm \frac{1}{2}$
Solution: Explanation: No Explanation
Inverse trigonometric functions

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