inv-trig

Question: ${{\tan }^{-1}}\frac{1-{{x}^{2}}}{2x}+{{\cos }^{-1}}\frac{1-{{x}^{2}}}{1+{{x}^{2}}}=$



1) $\frac{\pi }{4}$
2) $\frac{\pi }{2}$
3) $\pi $
4) 0
Solution: Explanation: No Explanation
Inverse trigonometric functions

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