Questions in statics

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Forces of 1, 2 unit act along the lines $x=0$and $y=0$. The equation of the line of action of the resultant is
If N is resolved in two components such that first is twice of other, the components are
O is the circumcentre of $\Delta ABC$. If the forces P, Q and R acting along OA, OB, and OC are in equilibrium then $P : Q : R$ is
Three forces P, Q and R acting on a particle are in equilibrium. If the angle between P and Q is double the angle between P and R, then P is equal to
Three forces P, Q, R are acting at a point in a plane. The angle between P, Q and Q, R are ${{150}^{o}}$and ${{120}^{o}}$ respectively, then for equilibrium; forces P, Q, R are in the ratio
If A, B ,C are three forces in equilibrium acting at a point and if ${{60}^{o}}$, ${{150}^{o}}$ and ${{150}^{o}}$respectively denote the angles between A and B, B and C and C and A, then the forces are in proportion of
If the angle $\alpha $ between two forces of equal magnitude is reduced to $\alpha -\frac{\pi }{3}$, then the magnitude of their resultant becomes $\sqrt{3}$times of the earlier one. The angle $\alpha $is
The resultant of two forces P and Q is R. If one of the forces is reversed in direction, the resultant becomes ${R}'$, then
Forces proportional to AB, BC and 2CA act along the sides of triangle ABC in order, their resultants represented in magnitude and direction is
$ABCD$ is a parallelogram. A particle P is attracted towards A and C by forces proportional to PA and PC respectively and repelled from B and D by forces proportional to $PB$and $PD$. The resultant of these forces is

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