statics

Question: The resultant of two forces P and Q is R. If one of the forces is reversed in direction, the resultant becomes ${R}'$, then

1) ${{{R}'}^{2}}={{P}^{2}}+{{Q}^{2}}+2PQ\cos \alpha $

2) ${{{R}'}^{2}}={{P}^{2}}-{{Q}^{2}}-2PQ\cos \alpha $

3) ${{{R}'}^{2}}+{{R}^{2}}=2({{P}^{2}}+{{Q}^{2}})$

4) ${{{R}'}^{2}}+{{R}^{2}}=2({{P}^{2}}-{{Q}^{2}})$

Solution:

Explanation: No Explanation

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