Questions in statics

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If two forces $P+Q$and $P-Q$make an angle $2\alpha $with each other and their resultant makes an angle $\theta $with the bisector of the angle between the two forces, then $\frac{P}{Q}$is equal to
The direction of three forces $1N$, $2N$ and $3N4 acting at a point are parallel to the sides of an equilateral triangle taken in order, The magnitude of their resultant is
Forces of magnitudes 5, 10, 15 and 20 Newton act on a particle in the directions of North, South, East and West respectively. The magnitude of their resultant is
Forces of magnitudes $P-Q,P$and $P+Q$act at a point parallel to the sides of an equilateral triangle taken in order. The resultant of these forces, is
Two forces acting in opposite directions on a particle have a resultant of 34 Newton; if they acted at right angles to one another, their resultant would have a magnitude of 50 Newton. The magnitude of the forces are
Three forces of magnitude 30, 60 and P acting at a point are in equilibrium. If the angle between the first two is ${{60}^{o}}$, the value of P is
The resultant of two forces P and Q acting at an angle $\theta $is equal to $(2m+1)$$\sqrt{{{P}^{2}}+{{Q}^{2}}}$; when they act at an angle ${{90}^{o}}-\theta $, the resultant is $(2m-1)$$\sqrt{{{P}^{2}}+{{Q}^{2}}}$; then $\tan \theta $=
If forces of magnitude P, Q and R act at a point parallel to the sides BC, CA and AB respectively of a $\Delta ABC$, then the magnitude of their resultant is
Two forces of magnitudes $P+Q$ and $P-Q$Newton are acting at an angle of ${{135}^{o}}$. If their resultant is a force of 2 Newton perpendicular to the line of action of the second force, then
Let R be the resultant of P and Q and if $\frac{P}{3}=\frac{Q}{7}=\frac{R}{5}$, then the angle between P and R is

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