statics

Question: Three forces P, Q and R acting on a particle are in equilibrium. If the angle between P and Q is double the angle between P and R, then P is equal to

1) $\frac{{{Q}^{2}}+{{R}^{2}}}{R}$

2) $\frac{{{Q}^{2}}-{{R}^{2}}}{Q}$

3) $\frac{{{Q}^{2}}-{{R}^{2}}}{R}$

4) $\frac{{{Q}^{2}}+{{R}^{2}}}{Q}$

Solution:

Explanation: No Explanation

Composition and resolution of forces and condition of equilibrium of forces

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