Questions in differentiation

Select	Question
	Given that $\frac{d}{{dx}}f(x) = f'(x)$. The relationship $f'(a + b) = f'(a)+ f'(b)$ is valid if $f(x)$ is equal to
	The derivative of $f(x) = \|x{\|^3}$ at $x = 0$ is
	If $y = \sqrt {\sin x + y} ,$ then $\frac{{dy}}{{dx}}$ equals to
	If $y = (1 + {x^2}){\tan ^{ - 1}}x - x,$then $\frac{{dy}}{{dx}} = $
	If $x = y\sqrt {1 - {y^2},} $then $\frac{{dy}}{{dx}} = $
	If $y = {\tan ^{ - 1}}\left[ {\frac{{\sin x + \cos x}}{{\cos x - \sin x}}} \right]\,,$ then $\frac{{dy}}{{dx}}$ is
	If $y = \frac{{a + b{x^{3/2}}}}{{{x^{5/4}}}}$ and $y' = 0$ at $x = 5$, then the ratio $a:b$ is equal to
	$\frac{d}{{dx}}\left[ {{{\tan }^{ - 1}}\left( {\frac{{a - x}}{{1 + ax}}} \right)} \right] = $
	$\frac{d}{{dx}}\left[ {\log \left\{ {{e^x}{{\left( {\frac{{x - 2}}{{x + 2}}} \right)}^{3/4}}} \right\}} \right]$ equals to
	If $y = \sec ({\tan ^{ - 1}}x),$then $\frac{{dy}}{{dx}}$ is