differentiation

Question: If $x = y\sqrt {1 - {y^2},} $then $\frac{{dy}}{{dx}} = $



1) 0
2) x
3) $\frac{{\sqrt {1 - {y^2}} }}{{1 - 2{y^2}}}$
4) $\frac{{\sqrt {1 - {y^2}} }}{{1 + 2{y^2}}}$
Solution: Explanation: Explanation
standard-differentiation

Rate this question:

Average rating: (0 votes)

Previous Question Next Question