differentiation

Question: The point of the curve ${{y}^{2}}=2(x-3)$ at which the normal is parallel to the line$y-2x+1=0$ is



1) (5,2)
2) $\left( -\frac{1}{2},-2 \right)$
3) (5, –2)
4) $\left( \frac{3}{2},\,2 \right)$
Solution: Explanation: No Explanation
Tangent and Normal

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