Questions in differentiation

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The derivative of $\sqrt {\sqrt x + 1} $is
If $y = {e^{\sqrt x }}$, then $\frac{{dy}}{{dx}}$equals
If $f(x) = {\cos ^{ - 1}}\left[ {\frac{{1 - {{(\log x)}^2}}}{{1 + {{(\log x)}^2}}}} \right]\,,$then the value of $f'(e) = $
The derivative of $f(x) = \,|{x^2} - x|$ at x = 2 is
If $f(1) = 3,\,f'(1) = 2,$then $\frac{d}{{dx}}\{ \log f\,({e^x} + 2x)\} $ at $x = 0$ is
$\frac{d}{{dx}}{\log _{\sqrt x }}(1/x)$is equal to
The value of $\frac{d}{{dx}}[|x - 1| + |x - 5|]$ at $x = 3$ is
$\frac{d}{{dx}}\left[ {\left( {\frac{{{{\tan }^2}2x - {{\tan }^2}x}}{{1 - {{\tan }^2}2x{{\tan }^2}x}}} \right)\cot 3x} \right]$
If $y = {\tan ^{ - 1}}\left( {\frac{{\sqrt x - x}}{{1 + {x^{3/2}}}}} \right),$then $y'(1)$ is
${10^{ - x\,\tan x}}\left[ {\frac{d}{{dx}}({{10}^{x\tan x}})} \right]$ is equal to

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