differentiation

Question: If $y = \sqrt {\sin x + y} ,$ then $\frac{{dy}}{{dx}}$ equals to



1) $\frac{{\sin x}}{{2y - 1}}$
2) $\frac{{\cos x}}{{2y - 1}}$
3) $\frac{{\sin x}}{{2y + 1}}$
4) $\frac{{\cos x}}{{2y + 1}}$
Solution: Explanation: Explanation
standard-differentiation

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