Questions in definite-integral

Select	Question
	The value of $\int_{0}^{2\pi }{{{\cos }^{99}}x\,dx}$ is
	If $[x]$ denotes the greatest integer less than or equal to $x,$ then the value of the integral $\int_{0}^{2}{{{x}^{2}}[x]\,dx}$ equals
	$\int_{\,0}^{\,\pi }{{{\cos }^{3}}x\,dx=}$
	$\int_{\,0}^{\,2\pi }{\|\sin x\|\,dx=}$
	$\int_{-3}^{3}{\frac{{{x}^{2}}\sin 2x}{{{x}^{2}}+1}\,dx=}$
	$\int_{\,0}^{\,\pi }{\log {{\sin }^{2}}x\,dx=}$
	If $f(x)$ is an odd function of $x,$ then $\int_{-\frac{\pi }{2}}^{\frac{\pi }{2}}{f(\cos x)\,dx}$ is equal to
	$\int_{0}^{\pi }{{{\sin }^{2}}x\,dx}$ is equal to
	$\int_{0}^{\pi /2}{\frac{\sin x}{\sin x+\cos x}\,dx}$ equals
	$\int_{-1}^{1}{x{{\tan }^{-1}}x\,dx}$ equals