definite-integral

Question: $\int_{-1}^{1}{x{{\tan }^{-1}}x\,dx}$ equals



1) $\left( \frac{\pi }{2}-1 \right)$
2) $\left( \frac{\pi }{2}+1 \right)$
3) $(\pi -1)$
4) 0
Solution: Explanation: No Explanation
Properties of definite integration

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