Questions in definite-integral

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	$\int_{\,-2}^{\,2}{\|x\|\,dx=}$
	Suppose f is such that $f(-x)=-f(x)$ for every real x and $\int_{\,0}^{\,1}{f(x)\,dx=5,}$ then $\int_{\,-\,1}^{\,0}{f(t)\,dt=}$
	Let ${{I}_{1}}=\int_{a}^{\pi -a}{xf(\sin x)dx,\,{{I}_{2}}=\int_{a}^{\pi -a}{\,\,f(\sin x)dx}}$, then ${{I}_{2}}$ is equal to
	$\int_{-\frac{1}{2}}^{\,\frac{1}{2}}{\cos x\,\ln \frac{1+x}{1-x}dx}$ is equal to
	The value of $\int_{\,{{e}^{-1}}}^{\,{{e}^{2}}}{\left\| \frac{{{\log }_{e}}x}{x} \right\|\,dx}$ is
	If $f(x)= \begin{cases} {{e}^{\cos x}}\sin x, & \|x\|\,\le 2 \\ 2, & \text{otherwise} \\ \end{cases}$, then $\int_{\,-\,2}^{\,3}{f(x)\,dx}$ is equal to
	If $f:R\to R$ and $g:R\to R$ are one to one, real valued functions, then the value of the integral $\int_{\,-\pi }^{\,\pi }{[f(x)+f(-x)]\,[g(x)-g(-x)]\,dx}$ is
	$\int_{\,\pi /6}^{\,\pi /3}{\,\frac{dx}{1+\sqrt{\cot x}}}$ is
	The value of $\int_{\,0}^{\,\pi /2}{\frac{{{\sin }^{2/3}}x}{{{\sin }^{2/3}}x+{{\cos }^{2/3}}x}dx}$ is
	$\int_{\,-\,1}^{\,1}{\log (x+\sqrt{{{x}^{2}}+1})\,dx=}$