Questions in definite-integral

Select	Question
	Let $f(x)$ be a non-negative continous function such that the area bounded by the curve $y=f(x)$, x-axis and the ordinates $x=\frac{\pi }{4}$, $x=\beta >\frac{\pi }{4}$ is $\left( \beta \sin \beta +\frac{\pi }{4}\cos \beta +\sqrt{2}\beta \right)$. Then $f\ \left( \frac{\pi }{2} \right)$ is
	Area bounded by curves $y={{x}^{2}}$ and $y=2-{{x}^{2}}$ is
	Let y be the function which passes through (1, 2) having slope $(2x+1)$. The area bounded between the curve and x-axis is