Questions in definite-integral

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Area bounded by the curve ${{x}^{2}}=4y$ and the straight line $x=4y-2$ is
The area of the region bounded by the curve $y=x|x|$, x-axis and the ordinates $x=1,\,\,x=-1$is given by
Area included between the two curves ${{y}^{2}}=4ax$ and ${{x}^{2}}=4ay,$ is
If the area bounded by $y=a{{x}^{2}}$and $x=a{{y}^{2}}$, $a>0$, is 1, then $a=$
The area bounded by the curves $y=\sqrt{x},$ $2y+3=x$ and $x-$axis in the 1st quadrant is
The area enclosed between the curve $y={{\log }_{e}}(x+e)$and the co-ordinate axes is
The parabolas ${{y}^{2}}=4x$ and ${{x}^{2}}=4y$ divide the square region bounded by the lines $x=4$, $y=4$and the coordinate axes. If ${{S}_{1}},{{S}_{2}},{{S}_{3}}$ are respectively the areas of these parts numbered from top to bottom, then ${{S}_{1}}:{{S}_{2}}:{{S}_{3}}$ is
If A is the area of the region bounded by the curve $y=\sqrt{3x+4}$, x axis and the line $x=-1$ and $x=4$and B is that area bounded by curve ${{y}^{2}}=3x+4$, x- axis and the lines $x=-1$and $x=4$ then $A:B$ is equal to
The area of the region bounded by the curve $9{{x}^{2}}+4{{y}^{2}}-36=0$ is
The area bounded by the curve $y={{(x+1)}^{2}},\,y={{(x-1)}^{2}}$ and the line $y=\frac{1}{4}$ is

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