definite-integral

Question: The parabolas ${{y}^{2}}=4x$ and ${{x}^{2}}=4y$ divide the square region bounded by the lines $x=4$, $y=4$and the coordinate axes. If ${{S}_{1}},{{S}_{2}},{{S}_{3}}$ are respectively the areas of these parts numbered from top to bottom, then ${{S}_{1}}:{{S}_{2}}:{{S}_{3}}$ is

1) $2:1:2$

2) $1:1:1$

3) $1:2:1$

4) $1:2:3$

Solution:

Explanation: No Explanation

Area bounded by region Volume and surface area of solids of revolution

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