A thin spherical conducting shell of radius $R$ has a charge q. Another charge Q is placed at the centre of the shell. The electrostatic potential at a point p a distance $\frac{R}{2}$ from the centre of the shell is

Question

Accepted Answer

$\frac{{2Q}}{{4\pi {\varepsilon _0}R}} + \frac{q}{{4\pi {\varepsilon _0}R}}$

Answer

$\frac{{(q + Q)}}{{4\pi {\varepsilon _0}}}\frac{2}{R}$

Answer

$\frac{{2Q}}{{4\pi {\varepsilon _0}R}}$

Answer

$\frac{{2Q}}{{4\pi {\varepsilon _0}R}} - \frac{{2q}}{{4\pi {\varepsilon _0}R}}$

Electrostatics

Question: A thin spherical conducting shell of radius $R$ has a charge q. Another charge Q is placed at the centre of the shell. The electrostatic potential at a point p a distance $\frac{R}{2}$ from the centre of the shell is

Electrostatics

Question: A thin spherical conducting shell of radius $R$ has a charge q. Another charge Q is placed at the centre of the shell. The electrostatic potential at a point p a distance $\frac{R}{2}$ from the centre of the shell is

Related Questions