Electrostatics

Related Questions

• A charged water drop whose radius is $0.1\,\mu m$ is in equilibrium in an electric field. If charge on it is equal to charge of an electron, then intensity of electric field will be $(g = 10\,m{s^{ - 1}})$

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• The distance between a proton and electron both having a charge $1.6 \times {10^{ - 19}}coulomb$, of a hydrogen atom is ${10^{ - 10}}metre$. The value of intensity of electric field produced on electron due to proton will be

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• An electron moving with the speed $5 \times {10^6}$ per sec is shooted parallel to the electric field of intensity $1 \times {10^3}N/C$. Field is responsible for the retardation of motion of electron. Now evaluate the distance travelled by the electron before coming to rest for an instant (mass of $e = 9 \times {10^{ - 31}}Kg.$ charge $= 1.6 \times {10^{ - 19}}C)$

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• A given charge is situated at a certain distance from an electric dipole in the end-on position experiences a force F. If the distance of the charge is doubled, the force acting on the charge will be

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• The electric field due to a charge at a distance of 3 m from it is 500 N/coulomb. The magnitude of the charge is $\left[ {\frac{1}{{4\pi {\varepsilon _0}}} = 9 \times {{10}^9}\frac{{N - {m^2}}}{{coulom{b^2}}}} \right]$

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