If $q$ is the charge per unit area on the surface of a conductor, then the electric field intensity at a point on the surface is

Question

Accepted Answer

$\left( {\frac{q}{{{\varepsilon _0}}}} \right)$ normal to surface

Answer

$\left( {\frac{q}{{2{\varepsilon _0}}}} \right)$ normal to surface

Answer

$\left( {\frac{q}{{{\varepsilon _0}}}} \right)$ tangential to surface

Answer

$\left( {\frac{q}{{2{\varepsilon _0}}}} \right)$ tangential to surface

Electrostatics