Electrostatics

Question: Four charges are placed on corners of a square as shown in figure having side of $5\,cm$. If Q is one microcoulomb, then electric field intensity at centre will be



1) $1.02 \times {10^7}N/C$ upwards
2) $2.04 \times {10^7}N/C$ downwards
3) $2.04 \times {10^7}N/C$ upwards
4) $1.02 \times {10^7}N/C$ downwards
Solution: Explanation: Explanation
electric-field-potential

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