Electrostatics

Question: The distance between a proton and electron both having a charge $1.6 \times {10^{ - 19}}coulomb$, of a hydrogen atom is ${10^{ - 10}}metre$. The value of intensity of electric field produced on electron due to proton will be



1) $2.304 \times {10^{ - 10}}N/C$
2) $14.4\,V/m$
3) $16\,V/m$
4) $1.44 \times {10^{11}}N/C$
Solution: Explanation: Explanation
electric-field-potential

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