Electrostatics

Question: A charged water drop whose radius is $0.1\,\mu m$ is in equilibrium in an electric field. If charge on it is equal to charge of an electron, then intensity of electric field will be $(g = 10\,m{s^{ - 1}})$



1) $1.61\,N/C$
2) $26.2\,N/C$
3) $262\,N/C$
4) $1610\,N/C$
Solution: Explanation: Explanation
electric-field-potential

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