Electrostatics

Question: Two equal charges $q$ are placed at a distance of $2a$ and a third charge $- 2q$ is placed at the midpoint. The potential energy of the system is

1) $\frac{{{q^2}}}{{8\pi {\varepsilon _0}a}}$

2) $\frac{{6{q^2}}}{{8\pi {\varepsilon _0}a}}$

3) $- \frac{{7{q^2}}}{{8\pi {\varepsilon _0}a}}$

4) $\frac{{9{q^2}}}{{8\pi {\varepsilon _0}a}}$

Solution:

Explanation: Explanation

electric-field-potential

Rate this question:

★ ★ ★ ★ ★

Average rating: (0 votes)