Electrostatics

Question: Equal charges $q$are placed at the vertices $A$ and $B$ of an equilateral triangle $ABC$ of side $a$. The magnitude of electric field at the point $C$ is

1) $\frac{q}{{4\pi {\varepsilon _0}{a^2}}}$

2) $\frac{{\sqrt 2 \,q}}{{4\pi {\varepsilon _0}{a^2}}}$

3) $\frac{{\sqrt 3 \,q}}{{4\pi {\varepsilon _0}{a^2}}}$

4) $\frac{q}{{2\pi {\varepsilon _0}{a^2}}}$

Solution:

Explanation: Explanation

electric-field-potential

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