Electrostatics

Question: The displacement of a charge Q in the electric field $E = {e_1}\hat i + {e_2}\hat j + {e_3}\hat k$ is $\hat r = a\hat i + b\hat j$. The work done is

1) $Q(a{e_1} + b{e_2})$

2) $Q\sqrt {{{(a{e_1})}^2} + {{(b{e_2})}^2}} $

3) $Q({e_1} + {e_2})\sqrt {{a^2} + {b^2}} $

4) $Q(\sqrt {e_1^2 + e_2^2)} \;(a + b)$

Solution:

Explanation: Explanation

electric-field-potential

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