Electrostatics

Question: The work done in carrying a charge of $5\mu \,C$ from a point A to a point B in an electric field is 10mJ. The potential difference $({V_B} - {V_A})$ is then



1) + 2kV
2) – 2 kV
3) + 200 V
4) – 200 V
Solution: Explanation: Explanation
electric-field-potential

Rate this question:

Average rating: (0 votes)

Previous Question Next Question