Dual Nature of Radiation and Matter

Question: An electron of mass m when accelerated through a potential difference V has de-Broglie wavelength $\lambda $. The de-Broglie wavelength associated with a proton of mass M accelerated through the same potential difference will be

1) $\lambda \frac{m}{M}$

2) $\lambda \sqrt {\frac{m}{M}} $

3) $\lambda \frac{M}{m}$ (d) $\lambda \sqrt {\frac{M}{m}} $

4)

Solution:

Explanation: No Explanation

Matter Waves

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