Two identical photo-cathodes receive light of frequencies ${f_1}$ and ${f_2}$. If the velocities of the photo electrons (of mass $m$) coming out are respectively ${v_1}$ and ${v_2}$, then

Question

Accepted Answer

$v_1^2 - v_2^2 = \frac{{2h}}{m}\left( {{f_1} - {f_2}} \right)$

Answer

${v_1} - {v_2} = {\left[ {\frac{{2h}}{m}\left( {{f_1} - {f_2}} \right)} \right]^{1/2}}$

Answer

${v_1} + {v_2} = {\left[ {\frac{{2h}}{m}\left( {{f_1} + {f_2}} \right)} \right]^{1/2}}$

Answer

$v_1^2 + v_2^2 = \frac{{2h}}{m}\left( {{f_1} + {f_2}} \right)$

Dual Nature of Radiation and Matter

Question: Two identical photo-cathodes receive light of frequencies ${f_1}$ and ${f_2}$. If the velocities of the photo electrons (of mass $m$) coming out are respectively ${v_1}$ and ${v_2}$, then

Dual Nature of Radiation and Matter

Question: Two identical photo-cathodes receive light of frequencies ${f_1}$ and ${f_2}$. If the velocities of the photo electrons (of mass $m$) coming out are respectively ${v_1}$ and ${v_2}$, then

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