Dual Nature of Radiation and Matter

Question: For the Bohr's first orbit of circumference $2\pi r$, the de-Broglie wavelength of revolving electron will be

1) $2\pi r$

2) $\pi r$

3) $\frac{1}{{2\pi r}}$

4) $\frac{1}{{4\pi r}}$

Solution:

Explanation: No Explanation

Matter Waves

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