diff-equation

Question: Solution of the equation $({{e}^{x}}+1)ydy=(y+1){{e}^{x}}dx$ is



1) $c(y+1)({{e}^{x}}+1)+{{e}^{y}}=0$
2) $c(y+1)({{e}^{x}}-1)+{{e}^{y}}=0$
3) $c(y+1)({{e}^{x}}-1)-{{e}^{y}}=0$
4) $c(y+1)({{e}^{x}}+1)={{e}^{y}}$
Solution: Explanation: No Explanation
Variable separable type differential equations

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