diff-equation

Question: Solution of the equation $(1-{{x}^{2}})dy+xydx=x{{y}^{2}}dx$ is

1) ${{(y-1)}^{2}}(1-{{x}^{2}})=0$

2) ${{(y-1)}^{2}}{{(1-x)}^{2}}={{c}^{2}}{{y}^{2}}$

3) ${{(y-1)}^{2}}(1+{{x}^{2}})={{c}^{2}}{{y}^{2}}$

4) None of these

Solution:

Explanation: No Explanation

Variable separable type differential equations

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