The solution of the differential equation $(1-{{x}^{2}})(1-y)dx=xy(1+y)dy$ is

Question

Accepted Answer

$\log [x{{(1-y)}^{2}}]=\frac{{{x}^{2}}}{2}-\frac{{{y}^{2}}}{2}-2y+c$

Answer

$\log [x\,{{(1-y)}^{2}}]=\frac{{{x}^{2}}}{2}+\frac{{{y}^{2}}}{2}-2y+c$

Answer

$\log [x{{(1-y)}^{2}}]=\frac{{{x}^{2}}}{2}-\frac{{{y}^{2}}}{2}+2y+c$

Answer

$\log [x{{(1+y)}^{2}}]=\frac{{{x}^{2}}}{2}+\frac{{{y}^{2}}}{2}+2y+c$

diff-equation