definite-integral

Question: Area bounded by curve $y=k\sin x$between $x=\pi $ and $x=2\pi ,$ is



1) $2k$ sq. unit
2) 0
3) $\frac{{{k}^{2}}}{2}$ sq. unit
4) $k$ sq. unit
Solution: Explanation: No Explanation
Area bounded by region Volume and surface area of solids of revolution

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