definite-integral

Related Questions

• The parabolas ${{y}^{2}}=4x$ and ${{x}^{2}}=4y$ divide the square region bounded by the lines $x=4$, $y=4$and the coordinate axes. If ${{S}_{1}},{{S}_{2}},{{S}_{3}}$ are respectively the areas of these parts numbered from top to bottom, then ${{S}_{1}}:{{S}_{2}}:{{S}_{3}}$ is

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• $\int_{\,-2}^{\,2}{|x|\,dx=}$

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• $\int_{0}^{\pi /2}{\frac{dx}{2+\cos x}}=$

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• If A is the area of the region bounded by the curve $y=\sqrt{3x+4}$, x axis and the line $x=-1$ and $x=4$and B is that area bounded by curve ${{y}^{2}}=3x+4$, x- axis and the lines $x=-1$and $x=4$ then $A:B$ is equal to

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• $\int_{0}^{\pi /6}{(2+3{{x}^{2}})\cos 3x\,dx=}$

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