definite-integral

Question: $\int_{0}^{\pi /6}{(2+3{{x}^{2}})\cos 3x\,dx=}$



1) $\frac{1}{36}(\pi +16)$
2) $\frac{1}{36}(\pi -16)$
3) $\frac{1}{36}({{\pi }^{2}}-16)$
4) $\frac{1}{36}({{\pi }^{2}}+16)$
Solution: Explanation: No Explanation
Fundamental definite integration Definite integration by substitution

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